1 | function y = digamma(x) |
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2 | %DIGAMMA Digamma function. |
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3 | % DIGAMMA(X) returns digamma(x) = d log(gamma(x)) / dx |
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4 | % If X is a matrix, returns the digamma function evaluated at each element. |
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5 | |
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6 | % Reference: |
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7 | % |
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8 | % J Bernardo, |
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9 | % Psi ( Digamma ) Function, |
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10 | % Algorithm AS 103, |
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11 | % Applied Statistics, |
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12 | % Volume 25, Number 3, pages 315-317, 1976. |
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13 | % |
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14 | % From http://www.psc.edu/~burkardt/src/dirichlet/dirichlet.f |
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15 | |
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16 | large = 9.5; |
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17 | d1 = -0.5772156649015328606065121; % digamma(1) |
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18 | d2 = pi^2/6; |
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19 | small = 1e-6; |
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20 | s3 = 1/12; |
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21 | s4 = 1/120; |
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22 | s5 = 1/252; |
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23 | s6 = 1/240; |
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24 | s7 = 1/132; |
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25 | s8 = 691/32760; |
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26 | s9 = 1/12; |
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27 | s10 = 3617/8160; |
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28 | |
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29 | % Initialize |
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30 | y = zeros(size(x)); |
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31 | |
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32 | % illegal arguments |
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33 | i = find(x == -Inf | isnan(x)); |
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34 | if ~isempty(i) |
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35 | x(i) = NaN; |
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36 | y(i) = NaN; |
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37 | end |
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38 | |
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39 | % Negative values |
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40 | i = find(x < 0); |
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41 | if ~isempty(i) |
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42 | % Use the reflection formula (Jeffrey 11.1.6): |
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43 | % digamma(-x) = digamma(x+1) + pi*cot(pi*x) |
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44 | y(i) = digamma(-x(i)+1) + pi*cot(-pi*x(i)); |
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45 | % This is related to the identity |
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46 | % digamma(-x) = digamma(x+1) - digamma(z) + digamma(1-z) |
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47 | % where z is the fractional part of x |
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48 | % For example: |
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49 | % digamma(-3.1) = 1/3.1 + 1/2.1 + 1/1.1 + 1/0.1 + digamma(1-0.1) |
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50 | % = digamma(4.1) - digamma(0.1) + digamma(1-0.1) |
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51 | % Then we use |
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52 | % digamma(1-z) - digamma(z) = pi*cot(pi*z) |
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53 | end |
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54 | |
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55 | i = find(x == 0); |
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56 | if ~isempty(i) |
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57 | y(i) = -Inf; |
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58 | end |
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59 | |
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60 | % Use approximation if argument <= small. |
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61 | i = find(x > 0 & x <= small); |
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62 | if ~isempty(i) |
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63 | y(i) = y(i) + d1 - 1 ./ x(i) + d2*x(i); |
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64 | end |
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65 | |
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66 | % Reduce to digamma(X + N) where (X + N) >= large. |
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67 | while(1) |
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68 | i = find(x > small & x < large); |
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69 | if isempty(i) |
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70 | break |
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71 | end |
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72 | y(i) = y(i) - 1 ./ x(i); |
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73 | x(i) = x(i) + 1; |
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74 | end |
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75 | |
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76 | % Use de Moivre's expansion if argument >= large. |
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77 | % In maple: asympt(Psi(x), x); |
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78 | i = find(x >= large); |
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79 | if ~isempty(i) |
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80 | r = 1 ./ x(i); |
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81 | y(i) = y(i) + log(x(i)) - 0.5 * r; |
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82 | r = r .* r; |
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83 | y(i) = y(i) - r .* ( s3 - r .* ( s4 - r .* (s5 - r .* (s6 - r .* s7)))); |
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84 | end |
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